Thermal Power Plant: Difference between revisions

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==Player Tips & Tricks==

===Burn Rates===

The duration a piece if fuel will last is based on its MJ value. Thermal generators suffer a 20% loss due to inefficiency. to calculate how long a Fuel unit will last, multiply the MJ rating by 80% (or 0.8), then divide it by the 2.16MW that the generator produces per second. The resulting number will be how long one unit of that fuel will last.<br>

The duration a piece of fuel will last is based on its MJ value. Thermal generators suffer a 20% loss due to inefficiency. to calculate how long a Fuel unit will last, multiply the MJ rating by 80% (or 0.8), then divide it by the 2.16MW that the generator produces per second. The resulting number will be how long one unit of that fuel will last.<br>

Example 1: Coal has a energy density of 2.7MJ. take away the efficiency loss (2.7 * 0.8) and you are left with 2.16MJ. Divide that by the thermal generators max production (2.16MJ / 2.16MW) and you get that one piece of coal will burn for one second at full use.<br>

Example 2: Hydrogen Fuel Rods has a energy density of 40MJ. take away the efficiency loss (40MJ * 0.8) and you are left with 32MJ. Divide that by the thermal generators max production (32MJ / 2.16MW) and you get that one Fuel Rod will burn for 14.8 seconds at full use.<br>

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 ==Player Tips & Tricks==
 ===Burn Rates===
-The duration a piece if fuel will last is based on its MJ value. Thermal generators suffer a 20% loss due to inefficiency. to calculate how long a Fuel unit will last, multiply the MJ rating by 80% (or 0.8), then divide it by the 2.16MW that the generator produces per second. The resulting number will be how long one unit of that fuel will last.<br>
+The duration a piece of fuel will last is based on its MJ value. Thermal generators suffer a 20% loss due to inefficiency. to calculate how long a Fuel unit will last, multiply the MJ rating by 80% (or 0.8), then divide it by the 2.16MW that the generator produces per second. The resulting number will be how long one unit of that fuel will last.<br>
 Example 1: Coal has a energy density of 2.7MJ. take away the efficiency loss (2.7 * 0.8) and you are left with 2.16MJ. Divide that by the thermal generators max production (2.16MJ / 2.16MW) and you get that one piece of coal will burn for one second at full use.<br>
 Example 2: Hydrogen Fuel Rods has a energy density of 40MJ. take away the efficiency loss (40MJ * 0.8) and you are left with 32MJ. Divide that by the thermal generators max production (32MJ / 2.16MW) and you get that one Fuel Rod will burn for 14.8 seconds at full use.<br>