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Example 2: Hydrogen Fuel Rods has a energy density of 40MJ. take away the efficiency loss (40MJ * 0.8) and you are left with 32MJ. Divide that by the thermal generators max production (32MJ / 2.16MW) and you get that one Fuel Rod will burn for 14.8 seconds at full use.<br> | Example 2: Hydrogen Fuel Rods has a energy density of 40MJ. take away the efficiency loss (40MJ * 0.8) and you are left with 32MJ. Divide that by the thermal generators max production (32MJ / 2.16MW) and you get that one Fuel Rod will burn for 14.8 seconds at full use.<br> | ||
[[Category:Item]] | [[Category:Item]] | ||
[[Category:Power Facility]] |
Revision as of 03:16, 29 January 2021
Energy Type | Thermal | |
Power | 2.16 MW | |
Energy Efficiency | 80% | |
Made In | Assembler | |
Hand-Make | Replicator | |
Stack Size | 50 |
Summary
Thermal Generators are a descendant of the old 20th century powerplants. Burning fossil fuels heats and boils water into steam, which spins generator turbines. Modern Advancements have allowed the water to be recycled, and more energy to be captured from the combustion process. Even with modern improvements, these generators still suffer from an 20% efficiency loss, reducing the amount of energy captured from fuel. Even with the efficiency loss, thermal generators are very compact, allowing only a few of them to power large factories. In the same space that 2 wind turbines take up, Thermal Generators produce over three times the power. They also run full time, unlike solar panels which are restricted to daytime operations.
Required Technology
Thermal Power |
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Production Chain
1 | 5 Sec <------ |
10 | 4 | 4 | 4 |
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1 | 1 Sec <------ |
1 |
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1 | 1 Sec <------ |
1 |
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1 | 1.5 Sec <------ |
1 |
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2 | 2 Sec <------ |
2 | 1 |
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Player Tips & Tricks
Burn Rates
The duration a piece if fuel will last is based on its MJ value. Thermal generators suffer a 20% loss due to inefficiency. to calculate how long a Fuel unit will last, multiply the MJ rating by 80% (or 0.8), then divide it by the 2.16MW that the generator produces per second. The resulting number will be how long one unit of that fuel will last.
Example 1: Coal has a energy density of 2.7MJ. take away the efficiency loss (2.7 * 0.8) and you are left with 2.16MJ. Divide that by the thermal generators max production (2.16MJ / 2.16MW) and you get that one piece of coal will burn for one second at full use.
Example 2: Hydrogen Fuel Rods has a energy density of 40MJ. take away the efficiency loss (40MJ * 0.8) and you are left with 32MJ. Divide that by the thermal generators max production (32MJ / 2.16MW) and you get that one Fuel Rod will burn for 14.8 seconds at full use.